General Divisibility Rules

In This Post we will learn some basic funda behind the Divisibility rules.
Question based on this are asked a Number of times in SSC CGL,CHSL and Banking. So it becomes necessary for us to learn this part in an elaborated manner.
Here is a table for you try to learn the table.

• Key Points To REMEMBER
  Number divisible by 2 =  only when Last digit of number is even.
  Number divisible by 4 = Last 2 digits number of number is divisible by 4.
  Number divisible by 8 = Last 3 digit is divisible by 8.
  Number divisible by 3 = sum of all the digits of number divisible by 3.
  Number divisible by 5 = last digit 0 or 5.
  Number divisible by 9 = sum of all the digits of  number divisible by 9.

Divisor	Divisibility condition	Examples
1	No special condition. Any integer is divisible by 1.	2 is divisible by 1.
2	The last digit is even (0, 2, 4, 6, or 8).	1,294: 4 is even.
3	Sum the digits. If the result is divisible by 3, then the original number is divisible by 3.	405 → 4 + 0 + 5 = 9 and 636 → 6 + 3 + 6 = 15 which both are clearly divisible by 3.
4	Examine the last two digits.	40832: 32 is divisible by 4.
	If the tens digit is even, the ones digit must be 0, 4, or 8.
	If the tens digit is odd, the ones digit must be 2 or 6.	40832: 3 is odd, and the last digit is 2.
	Twice the tens digit, plus the ones digit.	40832: 2 × 3 + 2 = 8, which is divisible by 4.
5	The last digit is 0 or 5.	495: the last digit is 5.
6	It is divisible by 2 and by 3.	1,458: 1 + 4 + 5 + 8 = 18, so it is divisible by 3 and the last digit is even, hence the number is divisible by 6.
7	Form the alternating sum of blocks of three from right to left.	1,369,851: 851 − 369 + 1 = 483 = 7 × 69
	Subtract 2 times the last digit from the rest. (Works because 21 is divisible by 7.)	483: 48 − (3 × 2) = 42 = 7 × 6.
	Or, add 5 times the last digit to the rest. (Works because 49 is divisible by 7.)	483: 48 + (3 × 5) = 63 = 7 × 9.
	Or, add 3 times the first digit to the next. (This works because 10a + b − 7a = 3a + b − last number has the same remainder)	483: 4×3 + 8 = 20 remainder 6, 6×3 + 3 = 21.
	Multiply each digit (from right to left) by the digit in the corresponding position in this pattern (from left to right): 1, 3, 2, -1, -3, -2 (repeating for digits beyond the hundred-thousands place). Then sum the results.	483595: (4 × (-2)) + (8 × (-3)) + (3 × (-1)) + (5 × 2) + (9 × 3) + (5 × 1) = 7.
8	If the hundreds digit is even, examine the number formed by the last two digits.	26.01666667
	If the hundreds digit is odd, examine the number obtained by the last two digits plus 4.	352: 52 + 4 = 56.
	Add the last digit to twice the rest.	56: (5 × 2) + 6 = 16.
	Examine the last three digits.	34152: Examine divisibility of just 152: 19 × 8
	Add four times the hundreds digit to twice the tens digit to the ones digit.	34152: 4 × 1 + 5 × 2 + 2 = 16
9	Sum the digits. If the result is divisible by 9, then the original number is divisible by 9.	2,880: 2 + 8 + 8 + 0 = 18: 1 + 8 = 9.
10	The last digit is 0.	130: the last digit is 0.
11	Form the alternating sum of the digits.	918,082: 9 − 1 + 8 − 0 + 8 − 2 = 22.
	Add the digits in blocks of two from right to left.[1]	627: 6 + 27 = 33.
	Subtract the last digit from the rest.	627: 62 − 7 = 55.
	Add the last digit to the hundredth place (add 10 times the last digit to the rest).	627: 62 + 70 = 132.
	If the number of digits is even, add the first and subtract the last digit from the rest.	918,082: the number of digits is even (6) → 1808 + 9 − 2 = 1815: 81 + 1 − 5 = 77 = 7 × 11
	If the number of digits is odd, subtract the first and last digit from the rest.	14,179: the number of digits is odd (5) → 417 − 1 − 9 = 407 = 37 × 11
12	It is divisible by 3 and by 4.	324: it is divisible by 3 and by 4.
	Subtract the last digit from twice the rest.	324: 32 × 2 − 4 = 60.
13	Form the alternating sum of blocks of three from right to left.	2,911,272: −2 + 911 − 272 = 637
	Add 4 times the last digit to the rest.	637: 63 + 7 × 4 = 91, 9 + 1 × 4 = 13.
	Subtract 9 times the last digit from the rest.	637: 63 - 63 = 0.
14	It is divisible by 2 and by 7.	224: it is divisible by 2 and by 7.
	Add the last two digits to twice the rest. The answer must be divisible by 14.	364: 3 × 2 + 64 = 70.
		1764: 17 × 2 + 64 = 98.
15	It is divisible by 3 and by 5.	390: it is divisible by 3 and by 5.
16	If the thousands digit is even, examine the number formed by the last three digits.	254,176: 176.
	If the thousands digit is odd, examine the number formed by the last three digits plus 8.	3,408: 408 + 8 = 416.
	Add the last two digits to four times the rest.	176: 1 × 4 + 76 = 80.
		1168: 11 × 4 + 68 = 112.
	Examine the last four digits.	157,648: 7,648 = 478 × 16.
17	Subtract 5 times the last digit from the rest.	221: 22 − 1 × 5 = 17.
18	It is divisible by 2 and by 9.	342: it is divisible by 2 and by 9.
19	Add twice the last digit to the rest.	437: 43 + 7 × 2 = 57.
20	It is divisible by 10, and the tens digit is even.	360: is divisible by 10, and 6 is even.
	If the number formed by the last two digits is divisible by 20.	480: 80 is divisible by 20.

||Number Systems||

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