Profit and Loss Problems

PROFIT AND LOSS PROBLEMS:


Q1. A man wanted to sell an article with 20% profit; but he actually sold at 20% loss for Rs 480. At what price (Rs) he wanted to sell it to earn the profit?
a) 720 b) 840 c) 600 d) 750

Q2. The cost price of 36 books is is equal to the selling price of 30 books. The gain per cent is:

a) 20% b) 50/3 % c) 18% d) 24%

Q3 A person sells two machines at Rs 396 each. One one he gains 10% and on the other he loses 10%. His profit or loss in the whole transaction is:

a) No gain no loss b) 1% loss c) 1% profit d) 8% profit

Q4. A house and a shop were sold for Rs 1 lakh each. In this transaction, the house sale resulted into 20% loss whereas the shop sale into 20% profit. The entire transaction resulted in

a) No loss no gain b) gain of Rs 1/24 lakh c) Loss of Rs 1/12 lakh d) Loss of Rs 1/18 lakh

Q5. A sells a bicycle to B at a profit of 20%. B sells it to C at a profit of 25%. If C pays Rs 225 /- for it, the cost price of the bicycle for A is:

a) Rs 110/- b) Rs 125 /- c) Rs 120 /- d) Rs 150/-

Q6. 12 copies of a book were sold for Rs 1800/- thereby gaining cost-price of 3 copies. The cost price of a copy is:

a) Rs 120 b) 150 c) RS 1200 d) Rs 1500

Q7. If a man estimates his loss as 20% of the selling price, then his loss per cent is:
a) 20% b) 25% c) 40/3% d) 50/3%

Q8. If I would have purchased 11 articles for Rs 1o and sold all the articles at the rate of 10 for Rs 11, the profit per cent would have been:

a) 10% b) 11% c) 21% d) 100%

Q9. An article is sold at a loss of 10%. Had it been sold for Rs 9 more, there would have been a gain of 25/2% on it. The cost price of the article is:

a) Rs 40 b) Rs 45 c) Rs 50 d) Rs 35

Q10. A man buys a cycle for Rs 1400 and sells it at a loss of 15%. What is the selling price of the cycle?

a) Rs 1202 b) Rs 1190 c) Rs 1160 d) Rs 1000

Q11. The ratio of cost price and selling price is 5: 4, the loss percent is:
a) 20% b0 25% c) 405 d) 50%

Q12.A person buys some pencils at 5 for a rupee and sells them at 3 for a rupee. His gain percent will be:
a) 200/3 b) 230/3 c) 170/3 d) 140/3

Q13. If selling price of an article is 8/5 times its cost price, the profit per cent on it is

a) 120% b) 160% c) 40% d) 60%

Q14. The price of coal is increased by 20%. By what per cent a family should decrease its consumption so that expenditure remains same?

a) 40% b) 70/3% c) 20% d) 50/3%

Q15: 100 oranges are bought for Rs 350 and sold at the rate of Rs 48 per dozen. The percentage of profit or loss is:

a) 15% loss b) 15% gain c) 100/7% loss d) 100/7% profit

Q16. A reduction of 20% in the price of salt enables a purchaser to obtain 4 kg more for Rs 100. The reduced price of salt per kg is:

a) Rs 4 b) Rs 5 c) Rs 6.25 d) Rs 6.50

Q17. A person sells a table at a profit of 10%. If he had bought the table at 5% less cost and sold for rs 80 more, he would have gained 20%. The cost price of the table is

a) Rs 3200 b) Rs 2500 c) Rs 2000 d) Rs 200

Q18. A person sells an article for Rs 75 and gains as much per cent as the cost price of the article in ruppes. The cost price of the article is:

a) Rs 37.50 b) Rs 40 c) Rs 50 d) RS 150

Q19. A man had 100 kg of sugar part of which he sold at 7% profit and rest at 17% profit. He gained 10% on the whole. How much did he sell at 7% profit?
a) 65 kg b) 35 kg c) 30 kg d) 70 kg

Q20. A person bought some articles at the rate of 5 per rupee and the same number at the rate of 4 per rupee. He mixed both the types and sold at the rate of 9 for 2 rupees. In this business he suffered a loss of rs 3. The total number of articles bought by him was:
a) 1090 b) 1080 c) 540 d) 545

Q21. A shopkeeper gains 20% while buying the goods and 30% while selling them. Find his total gain percent.

a) 505 b) 36% c) 56% d) 40%

Q22. The percentage of loss when an article is sold at rs 50 is the as that of the profit when it is sold at Rs 70. The above mentioned percentage of profit or loss on the article is

a) 10% b) 50/3% c) 20% d) 68/3
Profit and Loss : Answer Key

1 a
2 a
3 b
4 c
5 d
6 a
7 d
8 c
9 a
10 b
11 a
12 a
13 d
14 d
15 d
16 b
17 c
18 c
19 d
20 b
21 c
22 b

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16 comments:

  1. Dear Akash please check question no 15. It seems that this question needs some updation.

    ReplyDelete
  2. Dear,
    The Question is absolutely correct and its Answer is 100/7%
    Solution:
    As the statement 100 oranges cost 350 thus cost of 1 orange is 3.5 Rs.
    And he sell them for 48 a dozen then SP of one orange comes out to be 4 Rs.
    Profit% = (.5/3.5)x100 = 100/7%

    ReplyDelete
  3. Sir please check question 16 and please give the solution of question no 20

    ReplyDelete
  4. Hello Abhi,
    Question No. 16 is absolutely correct and its answer is 5.
    Solution: Let us assume the price of Salt be "X" and Quantity "Y"
    Total money = XY...........................1
    After reduction of Price the New Price Becomes = 0.8X
    And quantity becomes = Y + 4
    Money spent = 0.8X(Y+4)...................2
    Equating 1 and 2 we get,
    Y= 16,
    And as we are given money spent = 100,
    Then original price X = 100/16,
    And reduced Price = 0.8 x 100/16 = 5Rs. this is our answer.

    ReplyDelete
  5. And Regarding Q 20,
    Let us assume the quantity be "2X" of which "X" is bought at 5 for 1Rs. and other "X" is bought 4 for 1Rs.
    5 for 1 Rs.
    Then cost of one is 0.2 Rs. And total cost is 0.2X..................................1
    4 for 1 Rs.
    Then cost of one comes out to be 0.25 Rs. and Total cost 0.25X...............2
    Then Adding 1 and second we get,
    Cost price of 2X items =0.45X.....................................3

    Selling 9 for 2 Rs.
    Selling Price of one article becomes 2/9 Rs.
    And Selling of 2X item is 4X/9........................4
    As we incured loss of 3 Rs.
    Loss = C.P - S.P
    3 = .45X - 4X/9 =X/180
    therefore X = 180x3,
    Hence total items 2X = 1080.
    This is our Answer.

    ReplyDelete
  6. Please gv the solution fr que. no. 16.
    Thnq Sir. N keep posting such questions everyday.. this helps me to improve my problem solving ability.
    Sir there is a suggestion.. if u could please start a test series or smthing.. or post a kind of time table that many students like me can follow so datt v cn manage tym.. i wnt to again strt my preparation fr dis yr. SSC in intensive way...
    Thnx

    ReplyDelete
  7. Monika please see the above reply to Abhi we have already provided the solution and thank you for your suggestion we are working on it.

    ReplyDelete
  8. Sr 6qes ki koi short trick hai
    kya

    ReplyDelete
  9. Thank u swati for posting your doubt,
    Q6 can be easily solved by using the simple principle,
    As per statement cost of 12 notebook gains us the price of 3 notebooks,
    we can make a statement,
    12S.P=15C.P
    and we are given 12S.P=1800,
    Hence,
    C.P=1800/15=120 which is our answer.

    ReplyDelete
  10. purchased 11 for Rs 10......................(1)
    sold 10 for Rs 11....................................(2)
    Solving this problem is not a big deal but solving it quickly does matter,
    In such Questions we try to make the quantity for product same,

    Multiply eq(1) by 10 and eq(2) by 11,We get
    C.P of 110 products = Rs. 100
    S.P of 110 Products = Rs. 121,
    From the above eq we get to know the profit on this will be
    21% which is our Answer. Hope you understand it.

    ReplyDelete
  11. Sir please 4,17,22,19 question

    ReplyDelete
  12. Q4 According to question
    S.P of house and shop is same = 1lakh each,Total S.P = 2 lakh.........(1)
    profit on one is 20% and loss of 20% on other,
    Let x &y be CP of house and shop:
    1.2x = 1 ; x= 10/12
    0.8y= 1 ; y = 10/8
    total C.P= 10/12 + 10/8= 200/96................(2)
    subtracting (1 ) and (2) we get
    1/12 as the C.P is more so this is loss,
    ANSWER C)

    ReplyDelete
  13. Q 17
    Let C.P be "x"
    when sold at 10% profit the S.P = 1.1x
    it is purchased at 5% loss so new C.P = 0.95x
    And sold at 80 Rs more i.e S.P= 1.1x + 80,..........(1)
    Now he gains 20% New S.P = 1.2*0.95x=1.14x........(2)
    Comparing 1 and 2 we get,
    1.1x + 80= 1.14x
    from this we get x= 2000
    which is our Answer.

    ReplyDelete
  14. Q 22
    As per percentage Principle,
    let the C.P of product = y;
    let the Profit or loss % = x;
    when the product is sold x% loss the S.P =50;;
    i.e, {(100-x)y}/100=50..............(1)
    When sold at x% profit the S.P=70;
    ii.e, {(100+x)y}/100=70..................(2)
    Dividing 1 by 2 and solving we get
    x= 200/12=50/3
    which is our Answer.

    ReplyDelete
  15. Q 19:
    This Question can be solved in number of ways, the easiest is Mixture and alligation

    7% 17%
    10%
    7 : 3

    The ratio of mixture is in ratio
    part which is sold at 7% profit : part which is sold at 17% profit=7:3
    Total Amount is 100 kg
    Hence the Amount sold at 7% profit is 70 kg.

    ReplyDelete